Monday, February 13, 2012

Pythagoras post

3. Determine the length of each hypotenuse.

a)
c squared = a squared + b squared
c squared = 12 squared + 16 squared
c squared = (12 x 12) + (16 x 16)
c squared = 144 + 256
c squared = 400 cm squared
Then squared root "c" squared and square root 400 cm squared
c = 20 cm


b)
r squared = p squared + q squared
r squared = 16 squared + 30 squared
r squared = (16 x 16) + (30 x 30)
r squared = 256 + 900
r squared = 1156 m squared
Then square root "r" squared and then squared root 1156 m squared
r = 34 m

4. What is the length of each hypotenuse? Give your answer to the nearest tenth of a centimeter.
a)
z squared = x squared + y squared
z squared = 6 squared + 7 squared
z squared = (6 x 6) + (7 x 7)
z squared = 36 + 49
z squared = 85 cm squared
Then square root "z" squared and then square root 85 cm squared.
z = 9.21 cm

b)
d squared = b squared + c squared
d squared = 8 squared + 11 squared
d squared = (8 x 8) + (11 x 11)
d squared = 64 + 121
d squared = 185 cm squared
Then square root "d" squared and then square root 185 cm squared
d = 13.6 cm

5.
a) What is the area of each square attached?

a squared = 6 squared
a squared = 6 x 6
a squared = 36 cm squared

b squared = 8 squared
b squared = 8 x 8
b squared = 64 cm squared

b) c squared = a squared + b squared
c squared = 36 + 64
c squared = 100 cm squared

c) square root "c" squared and then square root 100 cm squared
c = 10 cm





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